3x2+13x-28=2x+2

Solution for 3x2+13x-28=2x+2 equation:

3x^2+13x-28=2x+2

We move all terms to the left:

3x^2+13x-28-(2x+2)=0

We get rid of parentheses

3x^2+13x-2x-2-28=0

We add all the numbers together, and all the variables

3x^2+11x-30=0

a = 3; b = 11; c = -30;
Δ = b2-4ac
Δ = 112-4·3·(-30)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-\sqrt{481}}{2*3}=\frac{-11-\sqrt{481}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+\sqrt{481}}{2*3}=\frac{-11+\sqrt{481}}{6}
$