3x2+-29x+40=0

Solution for 3x2+-29x+40=0 equation:

3x^2+-29x+40=0

We add all the numbers together, and all the variables

3x^2-29x=0

a = 3; b = -29; c = 0;
Δ = b2-4ac
Δ = -292-4·3·0
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-29}{2*3}=\frac{0}{6}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+29}{2*3}=\frac{58}{6}
=9+2/3
$