3x/6=(x-7)/9

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Solution for 3x/6=(x-7)/9 equation: 



3x/6=(x-7)/9

We move all terms to the left:

3x/6-((x-7)/9)=0

We calculate fractions


27x^2/()+(-((x-7)*6)/()=0



We calculate terms in parentheses: +(-((x-7)*6)/(), so:

-((x-7)*6)/(

We multiply all the terms by the denominator


-((x-7)*6)



We calculate terms in parentheses: -((x-7)*6), so:

(x-7)*6

We multiply parentheses

6x-42

Back to the equation:

-(6x-42)



We get rid of parentheses

-6x+42

Back to the equation:

+(-6x+42)



We get rid of parentheses

27x^2/()-6x+42=0

We multiply all the terms by the denominator


27x^2-6x*()+42*()=0

We add all the numbers together, and all the variables

27x^2-6x*()=0

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