3x/5=2(x-2)/3

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Solution for 3x/5=2(x-2)/3 equation: 



3x/5=2(x-2)/3

We move all terms to the left:

3x/5-(2(x-2)/3)=0

We calculate fractions


9x^2/()+(-(2(x-2)*5)/()=0



We calculate terms in parentheses: +(-(2(x-2)*5)/(), so:

-(2(x-2)*5)/(

We multiply all the terms by the denominator


-(2(x-2)*5)



We calculate terms in parentheses: -(2(x-2)*5), so:

2(x-2)*5

We multiply parentheses

10x-20

Back to the equation:

-(10x-20)



We get rid of parentheses

-10x+20

Back to the equation:

+(-10x+20)



We get rid of parentheses

9x^2/()-10x+20=0

We multiply all the terms by the denominator


9x^2-10x*()+20*()=0

We add all the numbers together, and all the variables

9x^2-10x*()=0

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