3x/4=(x+20)/8

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Solution for 3x/4=(x+20)/8 equation: 



3x/4=(x+20)/8

We move all terms to the left:

3x/4-((x+20)/8)=0

We calculate fractions


24x^2/()+(-((x+20)*4)/()=0



We calculate terms in parentheses: +(-((x+20)*4)/(), so:

-((x+20)*4)/(

We multiply all the terms by the denominator


-((x+20)*4)



We calculate terms in parentheses: -((x+20)*4), so:

(x+20)*4

We multiply parentheses

4x+80

Back to the equation:

-(4x+80)



We get rid of parentheses

-4x-80

Back to the equation:

+(-4x-80)



We get rid of parentheses

24x^2/()-4x-80=0

We multiply all the terms by the denominator


24x^2-4x*()-80*()=0

We add all the numbers together, and all the variables

24x^2-4x*()=0

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