3x/4-13/28=(2/7)x

Solution for 3x/4-13/28=(2/7)x equation:

3x/4-13/28=(2/7)x

We move all terms to the left:

3x/4-13/28-((2/7)x)=0


Domain of the equation: 7)x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

3x/4-((+2/7)x)-13/28=0

We calculate fractions


588x^2/784x+()/784x+(-2548x)/784x=0

We multiply all the terms by the denominator


588x^2+(-2548x)+()=0

We add all the numbers together, and all the variables

588x^2+(-2548x)=0

We get rid of parentheses

588x^2-2548x=0

a = 588; b = -2548; c = 0;
Δ = b2-4ac
Δ = -25482-4·588·0
Δ = 6492304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6492304}=2548$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2548)-2548}{2*588}=\frac{0}{1176}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2548)+2548}{2*588}=\frac{5096}{1176}
=4+1/3
$