3x/4(2x+1)=x/3+6x/9

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Solution for 3x/4(2x+1)=x/3+6x/9 equation:


x in (-oo:+oo)

((3*x)/4)*(2*x+1) = x/3+(6*x)/9 // - x/3+(6*x)/9

((3*x)/4)*(2*x+1)-(x/3)-((6*x)/9) = 0

((3*x)/4)*(2*x+1)-(x/3)+(-2/3)*x = 0

3/4*x*(2*x+1)-x/3+(-2*x)/3 = 0

(3/4*3*x*(2*x+1))/3-x/3+(-2*x)/3 = 0

3/4*3*x*(2*x+1)-x-2*x = 0

9/2*x^2+5/4*x-2*x = 0

9/2*x^2-3/4*x = 0

9/2*x^2-3/4*x = 0

3/2*x*(3*x-1/2) = 0

3*x-1/2 = 0 // + 1/2

3*x = 1/2 // : 3

x = 1/2/3

x = 1/6

3/2*x*(x-1/6) = 0

(3/2*x*(x-1/6))/3 = 0

(3/2*x*(x-1/6))/3 = 0 // * 3

3/2*x*(x-1/6) = 0

( 3/2*x )

3/2*x = 0 // : 3/2

x = 0

( x-1/6 )

x-1/6 = 0 // + 1/6

x = 1/6

x in { 0, 1/6 }

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