3x-x/3+(x+1)/6=9x

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Solution for 3x-x/3+(x+1)/6=9x equation: 


x in (-oo:+oo)

(x+1)/6+3*x-(x/3) = 9*x // - 9*x

(x+1)/6+3*x-(x/3)-(9*x) = 0

(x+1)/6+3*x-(x/3)-9*x = 0

(x+1)/6+3*x-x/3-9*x = 0

(3*(x+1))/(3*6)+(3*3*6*x)/(3*6)+(6*(-x))/(3*6)+(-9*3*6*x)/(3*6) = 0

3*(x+1)+3*3*6*x+6*(-x)-9*3*6*x = 0

57*x-6*x-162*x+3 = 0

51*x-162*x+3 = 0

3-111*x = 0

(3-111*x)/(3*6) = 0

(3-111*x)/(3*6) = 0 // * 3*6

3-111*x = 0

3-111*x = 0 // - 3

-111*x = -3 // : -111

x = -3/(-111)

x = 1/37

x = 1/37

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