3x-9=2(x-3)-3+x

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Solution for 3x-9=2(x-3)-3+x equation:


Simplifying
3x + -9 = 2(x + -3) + -3 + x

Reorder the terms:
-9 + 3x = 2(x + -3) + -3 + x

Reorder the terms:
-9 + 3x = 2(-3 + x) + -3 + x
-9 + 3x = (-3 * 2 + x * 2) + -3 + x
-9 + 3x = (-6 + 2x) + -3 + x

Reorder the terms:
-9 + 3x = -6 + -3 + 2x + x

Combine like terms: -6 + -3 = -9
-9 + 3x = -9 + 2x + x

Combine like terms: 2x + x = 3x
-9 + 3x = -9 + 3x

Add '9' to each side of the equation.
-9 + 9 + 3x = -9 + 9 + 3x

Combine like terms: -9 + 9 = 0
0 + 3x = -9 + 9 + 3x
3x = -9 + 9 + 3x

Combine like terms: -9 + 9 = 0
3x = 0 + 3x
3x = 3x

Add '-3x' to each side of the equation.
3x + -3x = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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