3x-8=2(x-1)+1

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Solution for 3x-8=2(x-1)+1 equation: 



3x-8=2(x-1)+1

We move all terms to the left:

3x-8-(2(x-1)+1)=0



We calculate terms in parentheses: -(2(x-1)+1), so:

2(x-1)+1

We multiply parentheses

2x-2+1

We add all the numbers together, and all the variables

2x-1

Back to the equation:

-(2x-1)



We get rid of parentheses

3x-2x+1-8=0

We add all the numbers together, and all the variables

x-7=0

We move all terms containing x to the left, all other terms to the right

x=7

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