3x-8/x=40

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Solution for 3x-8/x=40 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-(8/x) = 40 // - 40

3*x-(8/x)-40 = 0

3*x-8*x^-1-40 = 0

3*x^1-8*x^-1-40*x^0 = 0

(3*x^2-40*x^1-8*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-40*x^1-8*x^0) = 0

x^1

3*x^2-40*x-8 = 0

3*x^2-40*x-8 = 0

DELTA = (-40)^2-(-8*3*4)

DELTA = 1696

DELTA > 0

x = (1696^(1/2)+40)/(2*3) or x = (40-1696^(1/2))/(2*3)

x = (4*106^(1/2)+40)/6 or x = (40-4*106^(1/2))/6

x in { (40-4*106^(1/2))/6, (4*106^(1/2)+40)/6}

x in { (40-4*106^(1/2))/6, (4*106^(1/2)+40)/6 }

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