3x-8(2x+3)=-6(20x+5)

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Solution for 3x-8(2x+3)=-6(20x+5) equation: 



3x-8(2x+3)=-6(20x+5)

We move all terms to the left:

3x-8(2x+3)-(-6(20x+5))=0

We multiply parentheses

3x-16x-(-6(20x+5))-24=0



We calculate terms in parentheses: -(-6(20x+5)), so:

-6(20x+5)

We multiply parentheses

-120x-30

Back to the equation:

-(-120x-30)



We add all the numbers together, and all the variables

-13x-(-120x-30)-24=0

We get rid of parentheses

-13x+120x+30-24=0

We add all the numbers together, and all the variables

107x+6=0

We move all terms containing x to the left, all other terms to the right

107x=-6

x=-6/107

x=-6/107

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