3x-8(1-x)=-36+7x

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Solution for 3x-8(1-x)=-36+7x equation: 



3x-8(1-x)=-36+7x

We move all terms to the left:

3x-8(1-x)-(-36+7x)=0

We add all the numbers together, and all the variables

3x-8(-1x+1)-(7x-36)=0

We multiply parentheses

3x+8x-(7x-36)-8=0

We get rid of parentheses

3x+8x-7x+36-8=0

We add all the numbers together, and all the variables

4x+28=0

We move all terms containing x to the left, all other terms to the right

4x=-28

x=-28/4

x=-7

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