3x-7=3(2x+12)

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Solution for 3x-7=3(2x+12) equation:



3x-7=3(2x+12)
We move all terms to the left:
3x-7-(3(2x+12))=0
We calculate terms in parentheses: -(3(2x+12)), so:
3(2x+12)
We multiply parentheses
6x+36
Back to the equation:
-(6x+36)
We get rid of parentheses
3x-6x-36-7=0
We add all the numbers together, and all the variables
-3x-43=0
We move all terms containing x to the left, all other terms to the right
-3x=43
x=43/-3
x=-14+1/3

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