3x-7+x=4(x-2)+1-x

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Solution for 3x-7+x=4(x-2)+1-x equation: 



3x-7+x=4(x-2)+1-x

We move all terms to the left:

3x-7+x-(4(x-2)+1-x)=0

We add all the numbers together, and all the variables

4x-(4(x-2)+1-x)-7=0



We calculate terms in parentheses: -(4(x-2)+1-x), so:

4(x-2)+1-x

determiningTheFunctionDomain
4(x-2)-x+1

We add all the numbers together, and all the variables

-1x+4(x-2)+1

We multiply parentheses

-1x+4x-8+1

We add all the numbers together, and all the variables

3x-7

Back to the equation:

-(3x-7)



We get rid of parentheses

4x-3x+7-7=0

We add all the numbers together, and all the variables

x=0

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