3x-7(x-4)=8x+2(6-5x)

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Solution for 3x-7(x-4)=8x+2(6-5x) equation: 



3x-7(x-4)=8x+2(6-5x)

We move all terms to the left:

3x-7(x-4)-(8x+2(6-5x))=0

We add all the numbers together, and all the variables

3x-7(x-4)-(8x+2(-5x+6))=0

We multiply parentheses

3x-7x-(8x+2(-5x+6))+28=0



We calculate terms in parentheses: -(8x+2(-5x+6)), so:

8x+2(-5x+6)

We multiply parentheses

8x-10x+12

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

-4x-(-2x+12)+28=0

We get rid of parentheses

-4x+2x-12+28=0

We add all the numbers together, and all the variables

-2x+16=0

We move all terms containing x to the left, all other terms to the right

-2x=-16

x=-16/-2

x=+8

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