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3x-6=4x(x-24)
We move all terms to the left:
3x-6-(4x(x-24))=0
We calculate terms in parentheses: -(4x(x-24)), so:We get rid of parentheses
4x(x-24)
We multiply parentheses
4x^2-96x
Back to the equation:
-(4x^2-96x)
-4x^2+3x+96x-6=0
We add all the numbers together, and all the variables
-4x^2+99x-6=0
a = -4; b = 99; c = -6;
Δ = b2-4ac
Δ = 992-4·(-4)·(-6)
Δ = 9705
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(99)-\sqrt{9705}}{2*-4}=\frac{-99-\sqrt{9705}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(99)+\sqrt{9705}}{2*-4}=\frac{-99+\sqrt{9705}}{-8} $
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