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3x-6+x=2(x-3)
We move all terms to the left:
3x-6+x-(2(x-3))=0
We add all the numbers together, and all the variables
4x-(2(x-3))-6=0
We calculate terms in parentheses: -(2(x-3)), so:We get rid of parentheses
2(x-3)
We multiply parentheses
2x-6
Back to the equation:
-(2x-6)
4x-2x+6-6=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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