3x-6+4x2=6

Solution for 3x-6+4x2=6 equation:

3x-6+4x^2=6

We move all terms to the left:

3x-6+4x^2-(6)=0

We add all the numbers together, and all the variables

4x^2+3x-12=0

a = 4; b = 3; c = -12;
Δ = b2-4ac
Δ = 32-4·4·(-12)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{201}}{2*4}=\frac{-3-\sqrt{201}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{201}}{2*4}=\frac{-3+\sqrt{201}}{8}
$