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3x-5=4/x=2
We move all terms to the left:
3x-5-(4/x)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3x-(+4/x)-5=0
We get rid of parentheses
3x-4/x-5=0
We multiply all the terms by the denominator
3x*x-5*x-4=0
We add all the numbers together, and all the variables
-5x+3x*x-4=0
Wy multiply elements
3x^2-5x-4=0
a = 3; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·3·(-4)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{73}}{2*3}=\frac{5-\sqrt{73}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{73}}{2*3}=\frac{5+\sqrt{73}}{6} $
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