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3x-5+x=2(2x-5)
We move all terms to the left:
3x-5+x-(2(2x-5))=0
We add all the numbers together, and all the variables
4x-(2(2x-5))-5=0
We calculate terms in parentheses: -(2(2x-5)), so:We get rid of parentheses
2(2x-5)
We multiply parentheses
4x-10
Back to the equation:
-(4x-10)
4x-4x+10-5=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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