3x-5(x-4)=8+4x-20

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Solution for 3x-5(x-4)=8+4x-20 equation: 



3x-5(x-4)=8+4x-20

We move all terms to the left:

3x-5(x-4)-(8+4x-20)=0

We add all the numbers together, and all the variables

3x-5(x-4)-(4x-12)=0

We multiply parentheses

3x-5x-(4x-12)+20=0

We get rid of parentheses

3x-5x-4x+12+20=0

We add all the numbers together, and all the variables

-6x+32=0

We move all terms containing x to the left, all other terms to the right

-6x=-32

x=-32/-6

x=5+1/3

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