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3x-5(x-4)=2(x+10)
We move all terms to the left:
3x-5(x-4)-(2(x+10))=0
We multiply parentheses
3x-5x-(2(x+10))+20=0
We calculate terms in parentheses: -(2(x+10)), so:We add all the numbers together, and all the variables
2(x+10)
We multiply parentheses
2x+20
Back to the equation:
-(2x+20)
-2x-(2x+20)+20=0
We get rid of parentheses
-2x-2x-20+20=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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