3x-5(x-4)=-8+3x+13

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Solution for 3x-5(x-4)=-8+3x+13 equation: 



3x-5(x-4)=-8+3x+13

We move all terms to the left:

3x-5(x-4)-(-8+3x+13)=0

We add all the numbers together, and all the variables

3x-5(x-4)-(3x+5)=0

We multiply parentheses

3x-5x-(3x+5)+20=0

We get rid of parentheses

3x-5x-3x-5+20=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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