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3x-5(x-2)=2(1-x)
We move all terms to the left:
3x-5(x-2)-(2(1-x))=0
We add all the numbers together, and all the variables
3x-5(x-2)-(2(-1x+1))=0
We multiply parentheses
3x-5x-(2(-1x+1))+10=0
We calculate terms in parentheses: -(2(-1x+1)), so:We add all the numbers together, and all the variables
2(-1x+1)
We multiply parentheses
-2x+2
Back to the equation:
-(-2x+2)
-2x-(-2x+2)+10=0
We get rid of parentheses
-2x+2x-2+10=0
We add all the numbers together, and all the variables
8!=0
There is no solution for this equation
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