3x-5(x+5)=8(2x-2)

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Solution for 3x-5(x+5)=8(2x-2) equation: 



3x-5(x+5)=8(2x-2)

We move all terms to the left:

3x-5(x+5)-(8(2x-2))=0

We multiply parentheses

3x-5x-(8(2x-2))-25=0



We calculate terms in parentheses: -(8(2x-2)), so:

8(2x-2)

We multiply parentheses

16x-16

Back to the equation:

-(16x-16)



We add all the numbers together, and all the variables

-2x-(16x-16)-25=0

We get rid of parentheses

-2x-16x+16-25=0

We add all the numbers together, and all the variables

-18x-9=0

We move all terms containing x to the left, all other terms to the right

-18x=9

x=9/-18

x=-1/2

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