3x-4=1/2x+1

Solution for 3x-4=1/2x+1 equation:

3x-4=1/2x+1

We move all terms to the left:

3x-4-(1/2x+1)=0


Domain of the equation: 2x+1)!=0

x∈R


We get rid of parentheses

3x-1/2x-1-4=0

We multiply all the terms by the denominator


3x*2x-1*2x-4*2x-1=0

Wy multiply elements

6x^2-2x-8x-1=0

We add all the numbers together, and all the variables

6x^2-10x-1=0

a = 6; b = -10; c = -1;
Δ = b2-4ac
Δ = -102-4·6·(-1)
Δ = 124
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{124}=\sqrt{4*31}=\sqrt{4}*\sqrt{31}=2\sqrt{31}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{31}}{2*6}=\frac{10-2\sqrt{31}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{31}}{2*6}=\frac{10+2\sqrt{31}}{12}
$