3x-4/5+13/x=8/x+4

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Solution for 3x-4/5+13/x=8/x+4 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+13/x-(4/5) = 8/x+4 // - 8/x+4

3*x+13/x-(8/x)-(4/5)-4 = 0

3*x+13/x-8*x^-1-4/5-4 = 0

3*x^1+5*x^-1-24/5*x^0 = 0

(3*x^2-24/5*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2-24/5*x^1+5*x^0) = 0

x^1

3*x^2+(-24/5)*x+5 = 0

3*x^2+(-24/5)*x+5 = 0

DELTA = (-24/5)^2-(3*4*5)

DELTA = -924/25

DELTA < 0

x in { } 

x belongs to the empty set

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