3x-4+5x=10x-(3-2x)

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Solution for 3x-4+5x=10x-(3-2x) equation: 



3x-4+5x=10x-(3-2x)

We move all terms to the left:

3x-4+5x-(10x-(3-2x))=0

We add all the numbers together, and all the variables

3x+5x-(10x-(-2x+3))-4=0

We add all the numbers together, and all the variables

8x-(10x-(-2x+3))-4=0



We calculate terms in parentheses: -(10x-(-2x+3)), so:

10x-(-2x+3)

We get rid of parentheses

10x+2x-3

We add all the numbers together, and all the variables

12x-3

Back to the equation:

-(12x-3)



We get rid of parentheses

8x-12x+3-4=0

We add all the numbers together, and all the variables

-4x-1=0

We move all terms containing x to the left, all other terms to the right

-4x=1

x=1/-4

x=-1/4

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