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3x-4+2(x-5)=9x+9x+8-2x
We move all terms to the left:
3x-4+2(x-5)-(9x+9x+8-2x)=0
We add all the numbers together, and all the variables
3x+2(x-5)-(16x+8)-4=0
We multiply parentheses
3x+2x-(16x+8)-10-4=0
We get rid of parentheses
3x+2x-16x-8-10-4=0
We add all the numbers together, and all the variables
-11x-22=0
We move all terms containing x to the left, all other terms to the right
-11x=22
x=22/-11
x=-2
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