3x-4(7x-4)=2(6+4x)+5

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Solution for 3x-4(7x-4)=2(6+4x)+5 equation: 



3x-4(7x-4)=2(6+4x)+5

We move all terms to the left:

3x-4(7x-4)-(2(6+4x)+5)=0

We add all the numbers together, and all the variables

3x-4(7x-4)-(2(4x+6)+5)=0

We multiply parentheses

3x-28x-(2(4x+6)+5)+16=0



We calculate terms in parentheses: -(2(4x+6)+5), so:

2(4x+6)+5

We multiply parentheses

8x+12+5

We add all the numbers together, and all the variables

8x+17

Back to the equation:

-(8x+17)



We add all the numbers together, and all the variables

-25x-(8x+17)+16=0

We get rid of parentheses

-25x-8x-17+16=0

We add all the numbers together, and all the variables

-33x-1=0

We move all terms containing x to the left, all other terms to the right

-33x=1

x=1/-33

x=-1/33

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