3x-4(2x+5)=3(x-2)+19

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Solution for 3x-4(2x+5)=3(x-2)+19 equation:



3x-4(2x+5)=3(x-2)+19
We move all terms to the left:
3x-4(2x+5)-(3(x-2)+19)=0
We multiply parentheses
3x-8x-(3(x-2)+19)-20=0
We calculate terms in parentheses: -(3(x-2)+19), so:
3(x-2)+19
We multiply parentheses
3x-6+19
We add all the numbers together, and all the variables
3x+13
Back to the equation:
-(3x+13)
We add all the numbers together, and all the variables
-5x-(3x+13)-20=0
We get rid of parentheses
-5x-3x-13-20=0
We add all the numbers together, and all the variables
-8x-33=0
We move all terms containing x to the left, all other terms to the right
-8x=33
x=33/-8
x=-4+1/8

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