3x-4(2x+1)=6(1-x)-4

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Solution for 3x-4(2x+1)=6(1-x)-4 equation: 



3x-4(2x+1)=6(1-x)-4

We move all terms to the left:

3x-4(2x+1)-(6(1-x)-4)=0

We add all the numbers together, and all the variables

3x-4(2x+1)-(6(-1x+1)-4)=0

We multiply parentheses

3x-8x-(6(-1x+1)-4)-4=0



We calculate terms in parentheses: -(6(-1x+1)-4), so:

6(-1x+1)-4

We multiply parentheses

-6x+6-4

We add all the numbers together, and all the variables

-6x+2

Back to the equation:

-(-6x+2)



We add all the numbers together, and all the variables

-5x-(-6x+2)-4=0

We get rid of parentheses

-5x+6x-2-4=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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