3x-4(2-x)=3(x-2)-4x=

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Solution for 3x-4(2-x)=3(x-2)-4x= equation: 



3x-4(2-x)=3(x-2)-4x=

We move all terms to the left:

3x-4(2-x)-(3(x-2)-4x)=0

We add all the numbers together, and all the variables

3x-4(-1x+2)-(3(x-2)-4x)=0

We multiply parentheses

3x+4x-(3(x-2)-4x)-8=0



We calculate terms in parentheses: -(3(x-2)-4x), so:

3(x-2)-4x

We add all the numbers together, and all the variables

-4x+3(x-2)

We multiply parentheses

-4x+3x-6

We add all the numbers together, and all the variables

-1x-6

Back to the equation:

-(-1x-6)



We add all the numbers together, and all the variables

7x-(-1x-6)-8=0

We get rid of parentheses

7x+1x+6-8=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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