3x-4(2-3x)=5(x-5)-33

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Solution for 3x-4(2-3x)=5(x-5)-33 equation: 



3x-4(2-3x)=5(x-5)-33

We move all terms to the left:

3x-4(2-3x)-(5(x-5)-33)=0

We add all the numbers together, and all the variables

3x-4(-3x+2)-(5(x-5)-33)=0

We multiply parentheses

3x+12x-(5(x-5)-33)-8=0



We calculate terms in parentheses: -(5(x-5)-33), so:

5(x-5)-33

We multiply parentheses

5x-25-33

We add all the numbers together, and all the variables

5x-58

Back to the equation:

-(5x-58)



We add all the numbers together, and all the variables

15x-(5x-58)-8=0

We get rid of parentheses

15x-5x+58-8=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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