3x-4(2+3x)=32

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Solution for 3x-4(2+3x)=32 equation: 



3x-4(2+3x)=32

We move all terms to the left:

3x-4(2+3x)-(32)=0

We add all the numbers together, and all the variables

3x-4(3x+2)-32=0

We multiply parentheses

3x-12x-8-32=0

We add all the numbers together, and all the variables

-9x-40=0

We move all terms containing x to the left, all other terms to the right

-9x=40

x=40/-9

x=-4+4/9

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