3x-33=2(11-2x)

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Solution for 3x-33=2(11-2x) equation: 



3x-33=2(11-2x)

We move all terms to the left:

3x-33-(2(11-2x))=0

We add all the numbers together, and all the variables

3x-(2(-2x+11))-33=0



We calculate terms in parentheses: -(2(-2x+11)), so:

2(-2x+11)

We multiply parentheses

-4x+22

Back to the equation:

-(-4x+22)



We get rid of parentheses

3x+4x-22-33=0

We add all the numbers together, and all the variables

7x-55=0

We move all terms containing x to the left, all other terms to the right

7x=55

x=55/7

x=7+6/7

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