3x-3/2x-4=2/x-2

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Solution for 3x-3/2x-4=2/x-2 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x-((3/2)*x)-4 = 2/x-2 // - 2/x-2

3*x-((3/2)*x)-(2/x)-4+2 = 0

3*x+(-3/2)*x-2*x^-1-4+2 = 0

3/2*x^1-2*x^-1-2*x^0 = 0

(3/2*x^2-2*x^1-2*x^0)/(x^1) = 0 // * x^2

x^1*(3/2*x^2-2*x^1-2*x^0) = 0

x^1

(3/2)*x^2-2*x-2 = 0

(3/2)*x^2-2*x-2 = 0

DELTA = (-2)^2-(-2*4*(3/2))

DELTA = 16

DELTA > 0

x = (16^(1/2)+2)/(2*(3/2)) or x = (2-16^(1/2))/(2*(3/2))

x = 2 or x = -2/3

x in { -2/3, 2} 

x in { -2/3, 2 }

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