3x-3(3-4x)=5(x-4)-39

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Solution for 3x-3(3-4x)=5(x-4)-39 equation: 



3x-3(3-4x)=5(x-4)-39

We move all terms to the left:

3x-3(3-4x)-(5(x-4)-39)=0

We add all the numbers together, and all the variables

3x-3(-4x+3)-(5(x-4)-39)=0

We multiply parentheses

3x+12x-(5(x-4)-39)-9=0



We calculate terms in parentheses: -(5(x-4)-39), so:

5(x-4)-39

We multiply parentheses

5x-20-39

We add all the numbers together, and all the variables

5x-59

Back to the equation:

-(5x-59)



We add all the numbers together, and all the variables

15x-(5x-59)-9=0

We get rid of parentheses

15x-5x+59-9=0

We add all the numbers together, and all the variables

10x+50=0

We move all terms containing x to the left, all other terms to the right

10x=-50

x=-50/10

x=-5

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