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3x-3(2-x)+4x=2(5-3x)
We move all terms to the left:
3x-3(2-x)+4x-(2(5-3x))=0
We add all the numbers together, and all the variables
3x-3(-1x+2)+4x-(2(-3x+5))=0
We add all the numbers together, and all the variables
7x-3(-1x+2)-(2(-3x+5))=0
We multiply parentheses
7x+3x-(2(-3x+5))-6=0
We calculate terms in parentheses: -(2(-3x+5)), so:We add all the numbers together, and all the variables
2(-3x+5)
We multiply parentheses
-6x+10
Back to the equation:
-(-6x+10)
10x-(-6x+10)-6=0
We get rid of parentheses
10x+6x-10-6=0
We add all the numbers together, and all the variables
16x-16=0
We move all terms containing x to the left, all other terms to the right
16x=16
x=16/16
x=1
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