3x-2=x(x-3)-x(2+x)

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Solution for 3x-2=x(x-3)-x(2+x) equation: 



3x-2=x(x-3)-x(2+x)

We move all terms to the left:

3x-2-(x(x-3)-x(2+x))=0

We add all the numbers together, and all the variables

3x-(x(x-3)-x(x+2))-2=0



We calculate terms in parentheses: -(x(x-3)-x(x+2)), so:

x(x-3)-x(x+2)

We multiply parentheses

x^2-x^2-3x-2x

We add all the numbers together, and all the variables

-5x

Back to the equation:

-(-5x)



We get rid of parentheses

3x+5x-2=0

We add all the numbers together, and all the variables

8x-2=0

We move all terms containing x to the left, all other terms to the right

8x=2

x=2/8

x=1/4

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