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3x-2/3x-1=3
We move all terms to the left:
3x-2/3x-1-(3)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
3x-2/3x-4=0
We multiply all the terms by the denominator
3x*3x-4*3x-2=0
Wy multiply elements
9x^2-12x-2=0
a = 9; b = -12; c = -2;
Δ = b2-4ac
Δ = -122-4·9·(-2)
Δ = 216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{216}=\sqrt{36*6}=\sqrt{36}*\sqrt{6}=6\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-6\sqrt{6}}{2*9}=\frac{12-6\sqrt{6}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+6\sqrt{6}}{2*9}=\frac{12+6\sqrt{6}}{18} $
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