3x-2(x-8)=3+4(1-2x)

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Solution for 3x-2(x-8)=3+4(1-2x) equation: 



3x-2(x-8)=3+4(1-2x)

We move all terms to the left:

3x-2(x-8)-(3+4(1-2x))=0

We add all the numbers together, and all the variables

3x-2(x-8)-(3+4(-2x+1))=0

We multiply parentheses

3x-2x-(3+4(-2x+1))+16=0



We calculate terms in parentheses: -(3+4(-2x+1)), so:

3+4(-2x+1)

determiningTheFunctionDomain
4(-2x+1)+3

We multiply parentheses

-8x+4+3

We add all the numbers together, and all the variables

-8x+7

Back to the equation:

-(-8x+7)



We add all the numbers together, and all the variables

x-(-8x+7)+16=0

We get rid of parentheses

x+8x-7+16=0

We add all the numbers together, and all the variables

9x+9=0

We move all terms containing x to the left, all other terms to the right

9x=-9

x=-9/9

x=-1

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