3x-2(x-4)=-(x-5)+3

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Solution for 3x-2(x-4)=-(x-5)+3 equation: 



3x-2(x-4)=-(x-5)+3

We move all terms to the left:

3x-2(x-4)-(-(x-5)+3)=0

We multiply parentheses

3x-2x-(-(x-5)+3)+8=0



We calculate terms in parentheses: -(-(x-5)+3), so:

-(x-5)+3

We get rid of parentheses

-x+5+3

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We add all the numbers together, and all the variables

x-(-1x+8)+8=0

We get rid of parentheses

x+1x-8+8=0

We add all the numbers together, and all the variables

2x=0

x=0/2

x=0

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