3x-2(x-3)=4(x+1)-10

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Solution for 3x-2(x-3)=4(x+1)-10 equation: 



3x-2(x-3)=4(x+1)-10

We move all terms to the left:

3x-2(x-3)-(4(x+1)-10)=0

We multiply parentheses

3x-2x-(4(x+1)-10)+6=0



We calculate terms in parentheses: -(4(x+1)-10), so:

4(x+1)-10

We multiply parentheses

4x+4-10

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

x-(4x-6)+6=0

We get rid of parentheses

x-4x+6+6=0

We add all the numbers together, and all the variables

-3x+12=0

We move all terms containing x to the left, all other terms to the right

-3x=-12

x=-12/-3

x=+4

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