3x-2(x+4)=5+(1-2x)

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Solution for 3x-2(x+4)=5+(1-2x) equation: 



3x-2(x+4)=5+(1-2x)

We move all terms to the left:

3x-2(x+4)-(5+(1-2x))=0

We add all the numbers together, and all the variables

3x-2(x+4)-(5+(-2x+1))=0

We multiply parentheses

3x-2x-(5+(-2x+1))-8=0



We calculate terms in parentheses: -(5+(-2x+1)), so:

5+(-2x+1)

determiningTheFunctionDomain
(-2x+1)+5

We get rid of parentheses

-2x+1+5

We add all the numbers together, and all the variables

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

x-(-2x+6)-8=0

We get rid of parentheses

x+2x-6-8=0

We add all the numbers together, and all the variables

3x-14=0

We move all terms containing x to the left, all other terms to the right

3x=14

x=14/3

x=4+2/3

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