3x-2(x+2)=4(x-3)+7

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Solution for 3x-2(x+2)=4(x-3)+7 equation: 



3x-2(x+2)=4(x-3)+7

We move all terms to the left:

3x-2(x+2)-(4(x-3)+7)=0

We multiply parentheses

3x-2x-(4(x-3)+7)-4=0



We calculate terms in parentheses: -(4(x-3)+7), so:

4(x-3)+7

We multiply parentheses

4x-12+7

We add all the numbers together, and all the variables

4x-5

Back to the equation:

-(4x-5)



We add all the numbers together, and all the variables

x-(4x-5)-4=0

We get rid of parentheses

x-4x+5-4=0

We add all the numbers together, and all the variables

-3x+1=0

We move all terms containing x to the left, all other terms to the right

-3x=-1

x=-1/-3

x=1/3

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