3x-2(x+2)=4(x-2)-7

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Solution for 3x-2(x+2)=4(x-2)-7 equation: 



3x-2(x+2)=4(x-2)-7

We move all terms to the left:

3x-2(x+2)-(4(x-2)-7)=0

We multiply parentheses

3x-2x-(4(x-2)-7)-4=0



We calculate terms in parentheses: -(4(x-2)-7), so:

4(x-2)-7

We multiply parentheses

4x-8-7

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

x-(4x-15)-4=0

We get rid of parentheses

x-4x+15-4=0

We add all the numbers together, and all the variables

-3x+11=0

We move all terms containing x to the left, all other terms to the right

-3x=-11

x=-11/-3

x=3+2/3

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