3x-2(x+1)=4(2x+3)

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Solution for 3x-2(x+1)=4(2x+3) equation: 



3x-2(x+1)=4(2x+3)

We move all terms to the left:

3x-2(x+1)-(4(2x+3))=0

We multiply parentheses

3x-2x-(4(2x+3))-2=0



We calculate terms in parentheses: -(4(2x+3)), so:

4(2x+3)

We multiply parentheses

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

x-(8x+12)-2=0

We get rid of parentheses

x-8x-12-2=0

We add all the numbers together, and all the variables

-7x-14=0

We move all terms containing x to the left, all other terms to the right

-7x=14

x=14/-7

x=-2

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