3x-2(6-1x)=7x+2(5+1x)-6

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Solution for 3x-2(6-1x)=7x+2(5+1x)-6 equation: 



3x-2(6-1x)=7x+2(5+1x)-6

We move all terms to the left:

3x-2(6-1x)-(7x+2(5+1x)-6)=0

We add all the numbers together, and all the variables

3x-2(-1x+6)-(7x+2(x+5)-6)=0

We multiply parentheses

3x+2x-(7x+2(x+5)-6)-12=0



We calculate terms in parentheses: -(7x+2(x+5)-6), so:

7x+2(x+5)-6

We multiply parentheses

7x+2x+10-6

We add all the numbers together, and all the variables

9x+4

Back to the equation:

-(9x+4)



We add all the numbers together, and all the variables

5x-(9x+4)-12=0

We get rid of parentheses

5x-9x-4-12=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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